If it's not what You are looking for type in the equation solver your own equation and let us solve it.
6x^2+12x-16=0
a = 6; b = 12; c = -16;
Δ = b2-4ac
Δ = 122-4·6·(-16)
Δ = 528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{528}=\sqrt{16*33}=\sqrt{16}*\sqrt{33}=4\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{33}}{2*6}=\frac{-12-4\sqrt{33}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{33}}{2*6}=\frac{-12+4\sqrt{33}}{12} $
| 4x2+15x+20=0 | | 4a+2=a+11 | | 5a+2=3a-2 | | 2(x+7)+3(x+1)=0 | | 28-4m=-15+3m | | 22+4x=3x-8 | | -6-c=-1 | | -34=5x-9 | | 2-5y=-38 | | Y=4+3x,x=5 | | 17-9=x-4 | | 7x+(1)/(3)=-1 | | 7x+1/3=-1 | | (e+5)/9=(e+25)/5 | | 20=32000x | | 6(x+6)+5=59 | | t^2-11t+18=0t= | | g(9)=25−3(9) | | 2x-37=2 | | (4x+3)(x-2)=90 | | (8*10^-2)(15-3x)^3-(2x)^2=0 | | X/2-7=x/6-5 | | -5.1=y/7+6.1 | | -5.1=y/7 | | n+8=2n | | 48=-11t+182t | | 4(2d-7)=33 | | 4x+4=11x+8 | | 2(2x+2)=-4(4x+2)+5x | | 2(2+2)=-4(4x+2)+5x | | 3m+1=4m+4 | | 4(3x+2)=-2(5x-5)-5x |